Chemistry, asked by aasthasrivastavayug, 10 months ago

An open flask at 25degree celcius contains air.Calculate the temperature at which one 5th of an measured at 25 degree celcius escapes.

Answers

Answered by ritieshreddy
0

Answer:

Explanation:According to Charle's law - T is directly proportion to V

Thus V1/V2 =T1/T2

1 /1/5=298/T2

(Let volume at initial is 1 and after 27℃ temp. Volume remains 1/5 of initial volume)

T1=T2=396K

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