Question

an open flask containing air is heated from 400 k to 600 k.the pr of air left in the flask is

Answer 1

Answer:

PV= nRT

PV = Constant

n is inversely proportional to Temperature.

$\frac{n_{2} }{n_{1} } = \frac{T_{1} }{T_{2}}$

$n_{2} = n_{1} X \frac{400}{600}$

$n_{2} =\frac{2}{3} n_{1}$

Percentage left = 2/3 x 100 = 66.67%

Answer 2

Answer:

At constant pressure,

$\frac{v1}{t1} = \frac{v2}{t2} \: or \: \frac{v}{400} = \frac{v2}{600}$

∴

$v2 = \frac{3}{2} v$

Volume of air escaped =

$\frac{3}{2} v - v$

$= \frac{v}{2}$

% of air escaped =

$\frac{ \frac{v}{2} }{ \frac{3v}{2} } \times 100$

$= 33.33$