Question

An open flask contains air at 27°C. To what temperature it must be heated to expel 1/4 of air?

Answer 1

Let final volume be, $V_{2}$=y Pa;
Given, Initial Temperature is, $T_ {1}$ = $27 ^{°C}$ = 300 K
Let final temperature be, $T_ {2}$ = x K,
and, by given data, Initial Volume be, $V_{1}$ $= \frac{3}{4}$y Pa
So, by Charles Law,
$\frac {V_{1}}{ T_{1} } = \frac{V_{2}}{ T_{2} }}$
$\frac{\frac{3}{4}y}{300} = \frac{y}{x}$
$x = 400 K$
$i.e., x = 127^{°C}$

Answer 2

Answer:

hii

Explanation:

hope it will help

ans is 127 degree