An open flask has helium gas at 2atm and 327c the flask is heated to 527c at the same pressure the fraction of original gas remaining in the flask is
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for the volume being constant
applying gas law.
n1T1 = n2T2
=> n1*(327+273) = n2*(273+527)
=> n1*600 = n2*800
=> n1/n2 = 4/3
fraction of gas remaining in the flask is 3/4
Answered by
0
Answer:
3/4
Explanation:
T1 = 327+273
=600 K
T2 = 527+273
=800 K
T1/T2 = 600/800
= 3/4
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