Question

An open glass tube is immersed in mercury in such a way that a length of 8cm extends above the mercury level . the open end of the tube is raised vertically up by additional 46cm . what will be the length of air column above mercury in the tube now ?
,[Atmospheric pressure = 76cm of Hg]
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Answer 1

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Answer 2

Explanation :- In this question , The system is accelerating horizontally , hence the pressure in the vertival direction will remain unaffacted

i. e p₁ = p₀ + ρgh

Again , we have to use the concept that the pressure in the same level will be same .

For air trapped in tube , p₁v₁ = p₂v₂

p₁ = pₐₜₘ = ρg 76

V₁ = A × 8 [∵ A = area of cross section ]

• p₂ = pₐₜₘ - ρg(54-x)
• = ρg(22+x)

v₂ = A×x

At constant temprature

• p₁v₁ = p₂v₂
• ρg 76•A8 = ρg(22+x) Ax
• x²+ 22x-78×8
• x = 16 cm

length of the air column above mercury in the tube is 16cm