an open metal bucket is in san open metal bucket is in the shape of a frustum of a cone mounted on a hollow cylindrical base made of the same metal Ice sheet the diameters of the two circular ends of the bucket are 60 cm and 24 cm the total vertical height of the bucket is 31 cm and that of the cylindrical base is 7 cm find the area of metallic sheet used to make the bucket and also find the volume of water the bucket can hold
Answers
Answer:
Step-by-step explanation:
Area of metallic sheet used=CSA of frustum+CSA of cylinder +CSA of Base
CSA of frustum,
Diameter of bigger circular end=45cm
Radius=45/2=22.5cm
Diameter of smaller circular end=25cm
Radius=25/2=12.5cm
Height of the frustum=Total height of the bucket−Height of the circular base
40−6=34cm
Slant Height=
h
2
+(r
1
2
−r
2
)
2
=
34
2
+(22.5−(2.5)
2
)
=
1156+(10)
2
=
1256
Slant height=35−44cm
CSA of frustum=π(r
1
+r
2
)l=
7
22
(22.5+12.5)35.44
=
7
22
×35×35.44
=3898.4cm
2
Area of circular base
Base is a circular part with radius 25/2
Area of circular base=πr
2
=
7
22
×12.5×12=491.07cm
2
CSA of cylinder=2πrh=2×
7
22
×12.5×7=471.428
Area of metallic sheet used=3989.4+491.07+471.428
=4860.898cm²
44640.
length multiple height multiple breadth