Question

An open metal bucket is in the shape of frustum of cone of height 16cm with radii its lower and upper ends as 8 cm and 20 cm respectively find the cost of milk which can be completely fill the blanket at rupees 20 rupay used by is equal to 22 by 7

Answer 1

Answer:

  208.41

Step-by-step explanation:

Given An open metal bucket is in the shape of frustum of cone of height 16cm with radii its lower and upper ends as 8 cm and 20 cm respectively find the cost of milk which can be completely fill the blanket at rupees 20 rs use pi equal to 22 by 7

We know that frustum of cone is π h/3 (R^2 + R r + r^2) cubic cm

 h = 16, R = 20 and r = 8

= 22/7 x 16 / 3 (20^2 + 160 + 64)

= 16.7(400 + 160 + 64)

= 624 x 16.7

= 10,420 cubic cm

1 cubic cm = 0.001 litres

10,420 c c = 10.42 litres

So cost of milk will be 10.42 x 20 = Rs 208.4