An open metallic bucket is in the shape of frustum of a cone.If the diameters of the two circular ends of the bucket are 45 25
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I don't know the right answer please sorry
Answer:Total area of Metalic sheet used = Ab = 3348.025 cm²Total volume of water bucket can hold = V = 23707 cm³
Step-by-step explanation:
To find:1) Total Surface area of the bucket = Ab
2) Volume of the bucket = VbGiven: Bottom Diameter of the Bucket = d = 25 cmTop Diameter of the ucket = D = 45 cmHeight of the bucket = H = 24 cm1) Total area of metallic sheet used = Lateral area of frustum of the cone + Area of the bottom of the bucket (circular plate)∴ Area of the frustum of the bucket is given byAf = ∴Af = ∴Af = 3.14×35×[√(10²+24²)]∴Af = 109.9 × √(100+ 576)∴ Af = 109.9 × √676 = 109.9 × 26∴ Af = 2857.4 cm² ..... (1)Area of the bottom of the circular plate = AcAc = (×d²) / 4∴ Ac = 3.14 × 25² / 4 = 3.14 × 625 / 4∴ Ac = 490.625 cm² ...... (2)From eq. (1) and (2) we get the total area of the bucket, i.e. Area of metalic sheet requiredAb = Af + AcAb = 2857.4 + 490.625Ab = 3348.025 cm²2) Volume of the Bucket: VVolume of the frustum of the cone is given byV = (1/3) * H * (R² + r² + R*r)∴ V = (π/3) * 24 * {(45/2)² + (25/2)² + (45/2*25/2)}∴V = π8 * (2025 + 625 + 1125)/4∴ V = 3.14 × 8 × (3775 / 4)∴ V = 23707 cm³ Volume of the water bucket can hold = 23707 cm³
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