Question

an open rectangle tank has dimensions 200cm x 200cm x 40cm. find the cost of polishing its inner surface at the rate of rupees7.50 per m square. pls answer this quick

Answer 1

Answer:

For cuboidal tank

length (l)=200cm=2m

breadth(b)=200cm=2m

height(h)=40cm=0.4m

Inner Surface Area=LSA of tank+ Area of 1 base

=2(l+b)h+l×b

=2(2+2)0.4+(2×2)

=0.8×4+4

=3.2+4

=7.2m²

Cost of polishing=Inner Surface Area×Rate

=7.2×7.5

=Rs 54