an open rectangular cistern when measured from outside is 1.35m long 1.08m broad and 90cm deep it is made up of an iron which is 2.5cm thick find the capacity and the volume of iron used
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Answer:
Step-by-step explanation:
New length = 1.35−2(0.025)
=1.35−0.05
=1.3m
New breadth = 1.08−2(0.025)
=1.03m
New height = 0.9−2(0.025)
=0.85m
Thickness of iron = 2.5 cm
= 0.025 m
Capacity or volume of cistern = l×b×h
=1.3×1.03×0.85
=1.138m³
Volume of iron used = Volume of cistern (without considering the thickness of iron) - Volume of cistern (after considering the thickness of iron)
=L×B×H−l×b×h
=(1.35×1.08×0.9)−(1.138)
=1.312−1.138
=0.174m³
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