Math, asked by Samirsaini2565, 1 year ago

An open rectangular cistern when measured from outside is 1.35m long, 1.08m board and 90cm deep.It is made up of iron which is 2.5cm thick. Find the capacity of the cistern and the volume of the iron used.

Answers

Answered by pj6112004
12

Convert all dimensions into cm:

Find the volume of the whole cistern based on external measurement:

Volume = Length x Breadth x Height

Volume = 135 x 108 x 90 = 1,312,200 cm³

Find the internal dimension:

Length = 135 - 2.5 - 2.5 = 130 cm

Breadth = 108 - 2.5 - 2.5 = 103 cm

Height = 90 - 2.5 = 87.5 cm

Find the internal volume:

Volume = Length x Breadth x Height

Volume = 130 x 103 x 87.5 = 1,171,625 cm³

Find the volume of the iron used:

Iron used = 1,312,200 - 1,171,625 = 140, 575 cm³

If you need the answer in m³:

140, 575 cm³ = 140, 575 ÷ 100³ = 0.14m³ (nearest hundredth)

Answer: The volume of the capacity is 140, 575 cm³

Answered by nkumari4958
0

Answer:

External length of the cistern = 135 cm.

External breath of the cistern = 180 cm.

External depth of the cistern = 90 cm.

External volume of the cistern = (135 × 108×90) cm 3.

Internal length of the cistern= {(135-(2.5×2)} cm = 130 cm.

Internal breadth of the cistern ={108-(2.5×2)} cm = 103 cm

Internal depth of the cistern = (90-2.5) cm = 87.5 cm

Capacity of the cistern = it's internal volume = 1171625 cm 3.

Volume of iron used = ( external - internal volume )

= ( 1312200 - 1171625 ) cm 3 = 140575 cm 3.

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