An open rectangular tank of length 32 cm and breadth 28 cm contains water to a depth of 19 cm. 2580 circular metal discs of diameter 23mm and height 4 mm are dropped into the tank. find ;
i). the new height of water in the tank,
ii). the surface area of the tank that is in contact with the water after the discs have been added.
Answers
Answer:
Answer for part (i)=23.8cm
sorry i could not give answer for part(ii) hope someone else will give.
Here is explanation for part i
Step-by-step explanation:
Volume of tank with water= l*b*h
= 32 * 28 * 19
= 17024 cm^3
Volume of each circular disc( note that disc are of cylinderical shape)
= pie*r^2*h
= pie * 1.15^2 * 0.4 (note that i converted mm into cm)
= 1.66 cm^3
Volume of 2580 circular disc= 1.66 * 2580
= 4282.8 cm^3
Total Volume= 4282.8+17024
= 21306.8 cm^3
Height(cm) Volume(cm^3)
19 17024
x 21306.8
x=(19 * 21306.8)/17024
Height=23.7 cm
Hope you like my answer
Goodbye!