Question

An open resonating tube has fundamental frequency of 'n'.when half of its length is dipped into water then its fundamental frequency will be-
a.3n/2
b.n/7
c.3n
d.n

Answer 1

Answer:

option D - n is correct

Explanation:

Please refer the attachment

Hope this helps :))

Answer 2

Given:

An open resonating tube has fundamental frequency of 'n'

So fundamental frequency  $n=\frac{V}{2L}$

when half of its length is dipped into water

$L=\frac{L}{2}$   (half of open pipe)

$f=\frac{V}{4L}$

$f=\frac{V}{4(\frac{L}{2} )}$

$f=\frac{V}{2L}$

f=n   (where n=V/2L)

The correct option is "d"

Hence the fundamental frequency is n