Question

An open tank is made of iron sheet of 4m wide. If the dimensions of the tank are 15m,12m and 3m,find the cost of iron sheet at rs 22.50per m.

Answer 1

$\huge \pink{ \bf{Hey \: there !! }}$


$\huge \bf \underline {Given :- }$

→ Length of the tank = 15 m.

→ Breadth of the tank = 12 m.

→ Height of the tank = 3 m.

→ Width of the sheet = 4 m.


$\huge \red{\mid\bf \underline { \overline{Solution :- } } \mid}$



As we know tank is in the shape of cuboid .

And, it is open tank .

So, the Total surface area [ TSA ] of open tank = Lateral surface area + area of base .

= 2( l + b )h + l × b .

= 2( 15 + 12 ) × 3 + 15 × 12 .

= 6 × 27 + 180 .

= 162 + 180 .

= 342 m² .


Thus, Total area of sheet required = 342 m² .

And, it is given : Width of sheet = 4 m.

→ Area = Length × Width .

$\begin{lgathered}\sf \implies Length = \frac{area}{width} \\ \\ \sf \implies Length = \frac{342}{4}. \\ \\ \sf \large\therefore Length = 85.5m.\end{lgathered}$


Therefore, cost of sheet of length 85.5m at the rate of 22.50 per m² 
$\begin{lgathered}\sf = 85.5 \times 22.50. \\ \\ \sf \huge \blue{ \boxed{ \boxed{ \underline{= Rs \: 1923.75 .}}}}\end{lgathered}$ 



✔✔ Hence, it is solved ✅✅.



$\huge \orange{ \boxed{ \boxed{ \mathcal{THANKS}}}}$

Answer 2

here is your answer OK ⛲⛲⛲⛲⛲⛲


Length of the tank = 15 m.

Breadth of the tank = 12 m.
Height of the tank = 3 m.
Width of the sheet = 4 m.

so...... Total surface area of open tank = Lateral surface area + area of base .

= 2( l + b )h + l × b .

= 2( 15 + 12 ) × 3 + 15 × 12 .

= 162 + 180 .

= 342 m²


And, it is given : Width of sheet = 4 m.

→ Area = Length × Width .

length = 343/4= 85.5m

cost of sheet of length 85.5m at the rate of 22.50 per m²


22.50 x 85.5 = 1923.75

OK