An open tank of height H is completely filled and is kept on a table of height 2H. At what height from the ground, a small hole should be made in the wall of the tank, so that the range on ground becomes maximum?
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A small hole should be made in the tank at 1.5 H
To find:
Where a small hole should be made in the tank.
Given:
Height of tank = H
Height of the table = 2H
Solution:
Let required height from ground = h
V_e = √(2g(3H-h))
Where g is the acceleration due to gravity.
For vertical motion,
H= ½ gt^2
T= √(2h/g)
X= V_e *t = √(2g(3H-h)) * √(2h/g)
X= 2√(h(3H-h))
For maximum X
dX/dh = 0
d/dh (2√(h(3H-h))) = 0
3H-h-h = 0
h= 3H/2 =1.5H
Because this point is in the tank, the hole should be made at this point.
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