an open u tube contains mercury when 13.6 cm of water is poured into one of the arms of the tube then the mercury rise in the other is
The answer is 0.5 cm
But I am getting only 1 cm
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Answered by
97
Given height of water = 13.6 cm = 0.136 m
Density of mercury = 13600 kg/m³
Density of water = 1000 kg/m³
Now from pascal law we have
P₁ =P₂
1000 × g × 0.136 = 13600×g× 2x
Here x = rise in the mercury column on the other side of the manometer.
x = (1000 × 0.136)/(2×13600)
x =0.5 m
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