An open u tube is containing mercury kerosene of specific gravity 0.8 is poured into one of its limbs so that the length of column of kerosene is about 40 cm the level of mercury column in that limb is lowered approximately by how much?
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The mercury column in that limb is lowered approximately by 1.2 cm
Explanation:
- The pressure increases while moving down in a liquid, so we will add P=ρgh
- When moving down the tube, subtract ρgh when moving upward in the tube.
- Let’s write the pressure equation as we move from point A to B.
- PA+(ρgh)water−(ρgh)mercury=PB
Decrease in mercury level = Specific gravity x Length of column
Decrease in mercury level = 0.8 x 40
Decrease in mercury level = 13.6 x 2h
Decrease in mercury level = 1.2 cm
Hence the mercury column in that limb is lowered approximately by 1.2 cm
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A simple u tube contains Mercury to the same level in both arm . if water is poured to the a height of 13.6 cm in one arm , how much will be the rise in mecury level in other arm? given:13.6×10^3kgm-3 density of mecury &10^3 kgm-3 density of water ?
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