An open vessel at 27°C is heated until three-fifth of the air in it has been expelled. Assuming that the volume of the vessel remains constant, find the temperature to which the vessel has been heated.
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Answer:
477 K
Explanation:
Given :
T₁ = 27 C
In term of Kelvin
T₁ = 300 K
n₁ = 1 mol
n₂ = 1 - 3 / 5
n₂ = 0.4 mol
The volume of gas remains constant throughout process.
= > Pressure also remain constant.
n₁ R T₁ = n₂ R T₂
n₁ T₁ = n₂ T₂
T₂ = n₁ T₁ / n₂
Putting values here we get :
T₂ = 1 × 300 / 0.4 C
T₂ = 3000 / 4 C = 477 K
Therefore , 477 K temperature to which the vessel has been heated.
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