An open vessel containing air at 292 K was cooled to a certain temperature at which the number of moles of the
gaseous molecules increased by 25%. The final temperature of the vessel is
a) 234 K b) 25 K
c) 210 K d) – 40 K
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Answer:
From the ideal gas relation,
PV=nRT
Since the pressure and volume in the given problem is constant, we get
nT=constant
⇒n
1
T
1
=n
2
T
2
⇒T
2
=
1.25
T
1
=
1.25
292
=233.6 K=−39.4
o
C
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