Question

an open vessel containing air at a temperature of 10 degree Celsius is heated at constant pressure to 400 degree Celsius what fraction of the weight of a originally contained in this vessel is expelled

Answer 1

Initial temperature, T1 = (10 +273) K = 383 K

Final temperature, T2 = (400 + 273) K = 673 K

$n_{1}T_{1} =n_{2} T_{2}$$</p><p>[tex] \frac{n_{2}}{n_{1}} = \frac{383 K}{673 K}$

= 0.6

Fraction of the air expelled out = 1 - 0.6 = $\frac{2}{5}$

Answer 2

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