an open vessel containing air is heated from 27oc to 127oc. the fraction of air originally present which goes out of it is
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As the vessel is open the pressure remains constant and there is no change in the volume of vessel. Hence volume also constant. According to ideal gas equation PV=nRT n1 =1 T1 =300k, T2=400 k n2=? P1V1=n1 RT1 , P2 V2=n2RT n1/n2 = T2/T1 1/n2 =400/300 n2=3/4 The fraction of air present in vessel after heating n2=3/4 The fraction of air which goes out of the vessel =1-3/4 =1/4
As the vessel is open the pressure remains constant and there is no change in the volume of vessel. Hence volume also constant. According to ideal gas equation PV=nRT n1 =1 T1 =300k, T2=400 k n2=? P1V1=n1 RT1 , P2 V2=n2RT n1/n2 = T2/T1 1/n2 =400/300 n2=3/4 The fraction of air present in vessel after heating n2=3/4 The fraction of air which goes out of the vessel =1-3/4 =1/4
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