An Open Water Tank 12 m long 9 M wide and 4 m deep is to be made. Determine the cost of iron sheet required at rupees 25 per metre, if the sheet is 1.5 m wide.
Answers
Answered by
401
ANSWER:
Cost of iron sheet required to make open tank is ₹4600.
EXPLANATION:
L=12m ; W=9m ; D=4m
w=1.5m ; r=25 ₹/m ; Length of sheet required=s
Total sheet required to make open tank
A=LSA of cuboid+Area of Bottom of tank
A = [2D(L+W)] + [L×W]
= [2×4(12+9)] + [12×9]
= (8×21) + 108
= 168 + 108
= 276m²
We know that Area=Length * width
Area of sheet = s * w
276 = s × 1.5
∴ s = 276 / 1.5 = 184m
Length of sheet required = 184m
Cost of sheet = Length of sheet × rate
= s × r = 184 × 25 = ₹4600
NOTE:
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Cost of iron sheet required to make open tank is ₹4600.
EXPLANATION:
L=12m ; W=9m ; D=4m
w=1.5m ; r=25 ₹/m ; Length of sheet required=s
Total sheet required to make open tank
A=LSA of cuboid+Area of Bottom of tank
A = [2D(L+W)] + [L×W]
= [2×4(12+9)] + [12×9]
= (8×21) + 108
= 168 + 108
= 276m²
We know that Area=Length * width
Area of sheet = s * w
276 = s × 1.5
∴ s = 276 / 1.5 = 184m
Length of sheet required = 184m
Cost of sheet = Length of sheet × rate
= s × r = 184 × 25 = ₹4600
NOTE:
If you found this answer to be helpful, please vote this answer as BRAINLIEST ANSWER to help me get some points. Thanks ☺️
Answered by
9
Answer:
cost of the sheet = rupees 4600
Step-by-step explanation:
Given,
length =12m
breathe =9m
deep = 4m
the wide of sheet =1.5
the rate of rupees 25 per m
let , the length of sheet required be x
total sheet required to make open tank
Area= LSA of cuboid + area of bottom of tank
Area= [2D( L+W)]+[L+W]
=[2×4(12+9)]+[12+9]
=(8×21)+108
=168+108
=276
We know that Area=length ×width
Area of sheet =x×w
276=x×1.5
x=276/1.5
x=184m
therefor, length of sheet required 184m
cost of sheet =length of sheet × rate
=x×r
=184×25
=rupees 4600
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