An optagon has three equal angles each of measure 115°.If all the remaining angles have equal measure, find the measure of each of the these remaining angles.
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Answer: octagon have total 8 angles
Three angles are = 115
Remaining angles are of same length
= Let be 5x ( each angle =x)
Sum of total angles of octagon = 1080
So 3x 115 + 5x = 1080
5x = 1080- 345
x = 735/5
x = 147
So the angle will 147
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An octagon has got 8 sides and angles
Total sum of interior angles = 1080°
Three angles are equal. Let these angles be 'x'. Therefore x=115°
Let the other equal angles be 'y'
According to Angle sum property,
x + x + x + y + y + y + y + y = 1080°
3x + 5y = 1080°
3 (115) + 5y = 1080°
345 + 5y = 1080°
5y = 1080 - 345 = 735°
y = 735/5 = 147°
Therefore the answer is 147°
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Total sum of interior angles = 1080°
Three angles are equal. Let these angles be 'x'. Therefore x=115°
Let the other equal angles be 'y'
According to Angle sum property,
x + x + x + y + y + y + y + y = 1080°
3x + 5y = 1080°
3 (115) + 5y = 1080°
345 + 5y = 1080°
5y = 1080 - 345 = 735°
y = 735/5 = 147°
Therefore the answer is 147°
HOPE IT WOULD HELP U
PLS MARK IT AS BRAINLIEST
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