An optical fibre has a core material of refractive index of 1.55 and cladding material of refractive index of 1.50. The numerical aperture of the fibre is
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Answered by
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n21=c/v
=1.55/1.50
=31/30
=10.3/10
=1.03 ans
=1.55/1.50
=31/30
=10.3/10
=1.03 ans
Answered by
0
Concept introduction:
Optical fiber is considered as an innovative technology that helps to transmit information when light passes through a glass or optical fiber. Optical fiber contains different dimensions of glass fibers.
Given:
We have been given the refractive index of the core material along with the refractive index of the cladding material.
To find:
We have to find the numeric aperture of the fiber.
Solution:
According to the question,
refractive index = speed of light in vacuum/speed of light in medium
therefore, critical angle = sin^-1(n2/n1)
Therefore, numeric aperture = Root(n1^2 - n2^2)
= root([1.55]^2-[1.50]^2)
= 0.39
Final answer:
The numerical aperture of the fiber is 0.39
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