Question

An optical fibre has a core material of refractive index of 1.55 and cladding material of refractive index of 1.50. The numerical aperture of the fibre is

Answer 1

n21=c/v
=1.55/1.50
=31/30
=10.3/10
=1.03 ans

Answer 2

Concept introduction:

Optical fiber is considered as an innovative technology that helps to transmit information when light passes through a glass or optical fiber. Optical fiber contains different dimensions of glass fibers.

Given:

We have been given the refractive index of the core material along with the refractive index of the cladding material.

To find:

We have to find the numeric aperture of the fiber.

Solution:

According to the question,

refractive index = speed of light in vacuum/speed of light in medium

therefore, critical angle = sin^-1(n2/n1)

Therefore, numeric aperture = Root(n1^2 - n2^2)

= root([1.55]^2-[1.50]^2)

= 0.39

Final answer:

The numerical aperture of the fiber is 0.39

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