Question

An optical fibre has a numerical aperture of 0.20 and a cladding refractive index of 1.59. Determine the acceptance angle for the fibre in water which has a refractive index of 1.33.​

Answer 1

Explanation:

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Answer 2

Answer:

8.65° is the acceptance angle for the given fiber.

Explanation:

As given in the question 0.20 is the numerical aperture(Nₐ) of the given optical fiber and water's refractive index(n₀) is 1.33.

Let $\alpha$ be the acceptance angle for the given fiber.

numerical aperture(Nₐ) and acceptance angle($\alpha$) are related by the formula,

Nₐ=n₀sin$\alpha$

$\alpha =sin^{-1} (\frac{N_{a} }{n_{0} } )\\\alpha =sin^{-1} (\frac{0.20 }{1.33 } )$

On solving $\alpha$ =8.65°

Hence 8.65° is the acceptance angle for the given fiber having a refractive index of 1.33 .