An optical fibre has a numerical aperture of 0.20 and a cladding refractive index of 1.59. Determine the acceptance angle for the fibre in water which has a refractive index of 1.33.
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Answer:
8.65° is the acceptance angle for the given fiber.
Explanation:
As given in the question 0.20 is the numerical aperture(Nₐ) of the given optical fiber and water's refractive index(n₀) is 1.33.
Let be the acceptance angle for the given fiber.
numerical aperture(Nₐ) and acceptance angle() are related by the formula,
Nₐ=n₀sin
On solving =8.65°
Hence 8.65° is the acceptance angle for the given fiber having a refractive index of 1.33 .
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