Question

An optically inactive compound (A) having molecular formula C4H11N on treatment with HNO2 gave an alcohol (B). (B) on heating at 440K gave an alkene (C). (C) on treatment with HBr gave an optically active compound (D), having molecular formula C4H9 Br. Identify A, B, C and D.

Thanks!

Answer 1

Name of compounds are -

A Butylamine

B butanol

C but1ene

D 2-bromobutane

•Since, first compound contains four carbon atom and one nitrogen atom, compound will be butylamine.

•Amine group, on action of HNO2 will be converted into alcohol functional group, characterised by

-OH.

•Further, on heating with concentrated H2SO4, dehydration occurs. Thus alcoholic group converts into alkene.

•Next, addition reaction will occur with respect to Markonikoff's rule, for addition of HBr.

•Product formed will be 2-bromobutane.