An ordered pair (α, β) for which the system of linear equations
(1 + α)x + βy + z = 2
αx + (1 + β)y + z = 3
αx + βy + 2z = 2
has a unique solution, is:
(A) (2, 4) (B) (–3, 1)
(C) (–4, 2) (D) (1, –3)
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Answer:
options 1,2,4
Step-by-step explanation:
see attachment
for unique solutions
determinant not equal to zero
matrix formes by coffecient of x, y, z
should be singular
also see eq1
on solving I get
alpha -beta not equal to 2
also
we have to calculate
x= ∆1/∆, y=∆2/∆ ,z= ∆3/∆ ......1
so final conditions for unique solutions
delta, delta1, 2,3 all not equal to zero
we get beta not equal to 2 alpha not equal to -4
and from 3 deter.. beta not equal to 2
now see attachment s
Attachments:
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