Question

An ordinary cube has 4 blank faces, one face mark 2 and another marked 3, and then probability of obtaining 12 in 5 throws is

Answer 1

s
$= 123456 \\ {s} = 6 \\ event \: a \: such \: that \: upper \: face \: is \: 12 \\ n{a} = 2 \\ 6 \times 6 \times 6 \times 6 \times 6 \times 6 \times = 46656 \\ p{a} = n \\ p{a} = n{a} \div n{s} \\ \\ p{a} = \frac{0}{46656 } = 0 \\ a \\ p{a} = 0$
$= 123456 \\ {s} = 6 \\ event \: a \: such \: that \: upper \: face \: is \: 12 \ \ n{a} = 2 \\ 6 \times 6 \times 6 \times 6 \times 6 \times 6 \times = 46656 \\ p{a} = n \\ p{a} = n{a} \div n{s} \\ \\ p{a} = \frac{0}{46656 } = 0 \\ a \\ p{a} = 0$
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