an ordinary cube has four blank faces,one face marked 2 and one face marked 3.Then find the probability of obtaining total exactly 12 on 5 throws
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Asked on December 20, 2019 by
Daizzy Sehgal
An ordinary cube has four blank faces, one face marked 2, another marked 3. Then the probability of obtaining a total of exactly 12 in 5 throws is
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n= Total number of ways =6
5
To find the favorable number of ways, a total of 12 in 5 throws can be obtained in the following two ways only:
(i) One blank and four 3
′
s
(ii) Three 2
′
s and two 3
′
s
The number of ways in case (i) =
5
C
1
=5
and the number of ways in case (ii) =
5
C
2
=10
∴m= the favorable number of ways.
=5+10=15
Hence the required probability =
6
5
5
=
2592
5
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