Math, asked by reena23233, 1 year ago

an ordinary die is rolled. what is the probability that the number of dots on its upper face is 1. 3? 2. less than 3? 3. an even number ?4. 7?

Answers

Answered by anushka150204
30

Answer:

1. 1/6(actually you havent specified if the no. of dots are only 3 or 3 or more so the answer given is for 'only 3')

2. 2/6

3. 3/6 or 1/2

4. 0

Hope it helped!(please comment if you want any further explanation!)


reena23233: please explain these all
anushka150204: Okay so as it is an ordinary die ,it will have 6 faces and dots
anushka150204: Dont consider first one Okay so ya it will have 6 faces 1.Since out of 6 faces only one will have 3 dots..the probability will be 1/6 The others can be done in the same way
Answered by amitnrw
46

1/6  ,  1/3  , 1/2 , 0

Step-by-step explanation:

an ordinary die  has numbers from 1  to 6

NUmber of dots on the face = number that face represent

Dots on face can be  1   , 2  , 3 ,  4  , 5  , 6

1.  Number of 3 Dots  

Probaility =   1/6

2. Number of Dots less than 3 = 1 or 2 Dots  

Probability = 2/6  = 1/3

3 . An even number  = 2 , 4 , 6

Probability = 3/6  = 1/2

4  7 Dots  not possible Hence

Probability = 0

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