an ordinary die is rolled. what is the probability that the number of dots on its upper face is 1. 3? 2. less than 3? 3. an even number ?4. 7?
Answers
Answer:
1. 1/6(actually you havent specified if the no. of dots are only 3 or 3 or more so the answer given is for 'only 3')
2. 2/6
3. 3/6 or 1/2
4. 0
Hope it helped!(please comment if you want any further explanation!)
1/6 , 1/3 , 1/2 , 0
Step-by-step explanation:
an ordinary die has numbers from 1 to 6
NUmber of dots on the face = number that face represent
Dots on face can be 1 , 2 , 3 , 4 , 5 , 6
1. Number of 3 Dots
Probaility = 1/6
2. Number of Dots less than 3 = 1 or 2 Dots
Probability = 2/6 = 1/3
3 . An even number = 2 , 4 , 6
Probability = 3/6 = 1/2
4 7 Dots not possible Hence
Probability = 0
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