Question

An ore contain 15% iron . How much ore will be required to get 18% kg of iron.​

Answer 1

Answer: 180 kg of ore will be required to get 18 kg of iron.

Step-by-step explanation:

An ore contains 15% iron

15 kg of iron is present in 100 kg of ore

or, 1 kg of iron is present in 100/15 kg of ore

or, 18 kg of iron is present in $\frac{100*18}{15}$ kg of ore

=$\frac{20*5*6*3}{3*5}$ kg of ore

=20*6=120 kg of ore

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