Question

an ore contain 20% of zinc.How many kg of ore will be required to get 45 kg of zinc

Answer 1

$\frac{20}{100} x$= 45
$\frac{1}{5} x$ = 45
$x$ = 45×5
$x$ = 225 kg

The weight of the ore is 225 kg.

Answer 2

Answer:225 kg

Step-by-step explanation:

Percentage of zinc in the ore =20% in 1kg

To get 45 kg of zinc = 45 × 100

                                     ---------------

                                        20

= 225 kg