An ore contains 12% copper . How many Kg of the ore are required to get 69Kg of copper.
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575 kg because 12%of 575 is 69
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Percentage of copper in ore = 12%
Let the amount of ore Required be a
12 % of a = 69
=> 12a/100 = 69
=> a = 6900/12
=> a = 575 kg
Amount of ore Required to get 69 kg of copper = 575 kg
Let the amount of ore Required be a
12 % of a = 69
=> 12a/100 = 69
=> a = 6900/12
=> a = 575 kg
Amount of ore Required to get 69 kg of copper = 575 kg
gaurav2013c:
brainliest it if it helped.....
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