an ore contains 12% copper how many kilogram of or are required to get 69 kilogram of copper
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Let x be the total weight of Ore
We are given x*12/100 = 69
so, x = 6900/12
x = 575 Kg
So, 575 Kg of ore is needed
We are given x*12/100 = 69
so, x = 6900/12
x = 575 Kg
So, 575 Kg of ore is needed
vishalsingh18:
please explain why we equal the equation to 69
Answered by
4
We can sole this using unitary method
12% copper means
0.012kg copper in 1 kg of ore.
So 1 kg copper means (1000/120)kg of ore.
So 69kg copper means (1000/120)×69kg ore.
=8.33*69kg ore.
=575kg.
575kg ore is required to get 69 kg ore.
Hope it helps.
12% copper means
0.012kg copper in 1 kg of ore.
So 1 kg copper means (1000/120)kg of ore.
So 69kg copper means (1000/120)×69kg ore.
=8.33*69kg ore.
=575kg.
575kg ore is required to get 69 kg ore.
Hope it helps.
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