An ore contains 12% copper . How many kilograms of the ore are required to get 69 kg of copper?
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Answer:
Solution:-
Let the total quantity of the ore be 'x' kg
So, 12 % of that ore is copper.
According to the question.
(x*12)/100 = 69
12x/100 = 69
3x/25 = 69
3x = 69*25
3x = 1725
x = 1725/3
x = 575 kg
So, 575 kg ore is required to get 69 kg of copper.
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