An ore contains 15% iron . how many much ore will be required to get 18 kg of iron ?
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An ore contains 15% iron, means 1 kg of ore containes 0,15 kg of iron, therefore
1 kg ~ 0,15 kg
x kg ~ 18 kg
1/x = 0,15/18
0,15x = 18
x = 18 : 0,15
x = 120 kg
It needs 120 kg of ore to get 18 kg of iron
1 kg ~ 0,15 kg
x kg ~ 18 kg
1/x = 0,15/18
0,15x = 18
x = 18 : 0,15
x = 120 kg
It needs 120 kg of ore to get 18 kg of iron
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