Math, asked by yaswanth4745, 10 months ago

An ore contains 15%iron. How much ore will be required to get 18 kg of iron

Answers

Answered by skvijay36

3

Answer:

Step-by-step explanation:

∴ Mass required to obtain 18kg of iron is '120kg'. Answer: 100kg of an ore contains 15kg of iron. Then, 15/100 * x = 18kg ⇒ x = 1800kg / 15 = 120kg.

Answered by S10305

6

Answer:

Mass required to obtain 18kg of iron is '120kg'. Answer: 100kg of an ore contains 15kg of iron. Then, 15/100 * x = 18kg ⇒ x = 1800kg / 15 = 120kg.

Step-by-step explanation:

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