Question

an ore contains 15% iron. How much ore will be required to get 18 kg of iron?​

Answer 1

Answer:

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Step-by-step explanation:

From the question,

        100kg of an ore contains 15kg of iron.

Let mass required to obtain 18kg of iron be 'x'.

Then, 15/100 * x = 18kg  ⇒  x = 1800kg/15 = 120kg.

∴ Mass required to obtain 18kg of iron is '120kg'.