Question

an ore contains 15% iron how much ore will be required to get 18 kg of iron

Answer 1

Answer:

Step-by-step explanation:

100kg of an ore contains 15kg of iron.

Let mass required to obtain 18kg of iron be = x

Then, 15/100 * x =  18kg  ⇒  x =  1800kg / 15 = 120kg.

so the required amount would be 120 kg

Answer 2

Let the ore be x
15% of x=18
15/100*x=18
Now you can do the calculations and find the answer