an ore contains 18% of copper. how many kg of the ore are required to get 63kg of copper?
Answers
Answered by
38
18×x/100=63
9x/50=63
x=350kg
9x/50=63
x=350kg
adityakjha24:
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Answered by
109
Let X kg ore is required.
As ore contains 18% copper.
Copper needed = 63 kg
A/c to question
18 % of X = 63 kg
18X/100 =63
X = (63 ×100)÷18
X = 350 kg
Hope it helps
As ore contains 18% copper.
Copper needed = 63 kg
A/c to question
18 % of X = 63 kg
18X/100 =63
X = (63 ×100)÷18
X = 350 kg
Hope it helps
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