An ore contains 18 of copper. How many kg of the ore are required to get 63 kg of copper
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Answered by
25
let X kg ore is required
as ore contains 18 of copper
copper needed =63 kg
18 of X = 63 kg
18X /100 =63
X=(63 ×100)/100
X=350 kgs
hope it helps you
as ore contains 18 of copper
copper needed =63 kg
18 of X = 63 kg
18X /100 =63
X=(63 ×100)/100
X=350 kgs
hope it helps you
Answered by
0
Answer:
let X kg ore is required
as ore contains 18 of copper
copper needed =63 kg
18 of X = 63 kg
18X /100 =63
X=(63 ×100)/100
X=350 kgs
hope it helps you
Explanation:
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