An ore contains 18% of copper. How many kg of the ore is require to get 63 kg of copper.
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Let X kg ore is required.
As ore contains 18% copper.
Copper needed = 63 kg
A/c to question
18 % of X = 63 kg
18X/100 =63
X = (63 ×100)÷18
X = 350 kg
Hope it helps
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