Question

An ore contains 20% iron . how many much ore will be required to get 1500 kg of iron ?

Answer 1

1) an ore contains 1÷20×100 of iron
2)an iron contains 100÷20 ore
for 1500 kg of iron
= 100÷20×1500
= 7500
Therefore,7500 of ore will be required to get 1500 kg of iron