An ore contains 20% iron . how many much ore will be required to get 1500 kg of iron ?
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1) an ore contains 1÷20×100 of iron
2)an iron contains 100÷20 ore
for 1500 kg of iron
= 100÷20×1500
= 7500
Therefore,7500 of ore will be required to get 1500 kg of iron
2)an iron contains 100÷20 ore
for 1500 kg of iron
= 100÷20×1500
= 7500
Therefore,7500 of ore will be required to get 1500 kg of iron
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