An ore contains 20%zinc. How many kg of ore will be required to get 90 kg of zinc
Answers
Answered by
11
Answer:
20/100×a=45
a=45×100
a=45×5
there are a=225 kg ore required
I hope you like it
Answered by
8
Answer:
Let the quantity of ore be x.
Zinc = 20% = 20/100
A/Q,
20/100 × x = 90
x / 5 = 90
x = 90 × 5
x = 450kg ans.
Step-by-step explanation:
Hope it helps.
20thnks: Inbox.
Similar questions