Math, asked by ekjotkaur7, 8 months ago

An ore contains 20%zinc. How many kg of ore will be required to get 90 kg of zinc​

Answers

Answered by Anonymous
11

Answer:

20/100×a=45

a=45×100

a=45×5

there are a=225 kg ore required

I hope you like it

Answered by Anonymous
8

Answer:

Let the quantity of ore be x.

Zinc = 20% = 20/100

A/Q,

20/100 × x = 90

x / 5 = 90

x = 90 × 5

x = 450kg ans.

Step-by-step explanation:

Hope it helps.

20thnks: Inbox.

Similar questions