an ore contains 20% zinc.how many kg of ore will be required for getting 45 kg of zinc
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20/100×45 = 9 kg
hence, 9 kg of zinc is present in 1kg ore.
hence, ore required=45/9 kg = 5kg
hence, 9 kg of zinc is present in 1kg ore.
hence, ore required=45/9 kg = 5kg
nandu5115:
wrong aswer
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