Math, asked by sujeetkumar7551, 11 months ago

An ore contains 5% aluminum. To get 52kgs of aluminum the quantity of ore required is

Answers

Answered by nabha1111

4

Answer:

the quantity of ore required is

(5/100×52) kgs=2.6kgs

Answered by subbu96

2

Step-by-step explanation:

(5/100×52) kgs=2.6 jgs

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