An ore contains 70%of iron .how kilogram of the ore is needed to obtain 210 kg of iron.
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100kg of an ore contains 70% of iron
let's X kg of required 210 kg of iron
then ,
(70/100)*210=X
X=147kg
100kg of an ore contains 70% of iron
let's X kg of required 210 kg of iron
then ,
(70/100)*210=X
X=147kg
iswar7:
mai kisi ko ans de rha tha
sorry
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