Question

an ore contains 8% copper. how many kilograms of the ore are required to get 68 kg of copper?

Answer 1

let x kg ore are needed
so x*8%=68
>> 8x/100= 68
>>x=68*100/8
=850
850 kg ore is needed

Answer 2

Hi! Here's you answer...
Let the kilos of the ore =x
suppose we take 1kg ore then it will hv 8%of copper which is ( 1000* 8/100) = 80 g of copper so to get 68 kg of copper we hv to multiply 80 g with another number (80x=68000)....or divide 68 kg by 80 g ( 68000÷80) = 850kg....therefore 850 kg of ore are required to get 68 kg of copper
Hope it helps buddy
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