Question

an ore the contatins 12% copper. how many kilograms of the ore requred to get 69kg of copper?

Answer 1

$\large{\boxed{\bold{Answer:}}}$

Let the capacity of ore be x,

Copper is 12% of the ore,

$\large{\boxed{\bold{A.T.Q}}}$

$\frac{(x \times 12)}{100} = 69 \\ \\ = > \frac{12x}{100} =69 \\ \\ = > \frac{3x}{25} = 69 \\ \\ = > 3x = 69 \times 25 \\ \\ = > x = \frac{1725}{3} \\ \\ = > x = 575 \: kg$

575 kilograms of ore is required to get 69kg of copper.

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Answer 2

(x*12)/100 = 69
12x/100 = 69
3x/25 = 69
3x = 69*25
3x = 1725
x = 1725/3 
x = 575 kg

Mark brainliest