Question

An organ pipe of length 0.5 m is open at both ends.What is the frequency of its fundamental note

Answer 1

this is probably the answer

Answer 2

Given that,

Length of the organ pipe, l = 0.5 m

To find,

The frequency of its fundamental note.

Solution,

For an open pipe for both ends, the frequency of the fundamental note is given by :

$f=\dfrac{nv}{2l}$

For its fundamental note, n = 1

v is speed of sound, v = 343 m/s

So,

$f=\dfrac{1\times 343}{2\times 0.5}\\\\f=343\ Hz$

So, the frequency of its fundamental note is 343 m/s.

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An organ pipe of length 0.5 m is open at both ends.What is the frequency of its fundamental note

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